Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 11)
11.
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
81 min.
108 min.
144 min.
192 min.
Answer: Option
Explanation:

Let the slower pipe alone fill the tank in x minutes.

Then, faster pipe will fill it in x minutes.
3

1 + 3 = 1
x x 36

4 = 1
x 36

x = 144 min.

Discussion:
67 comments Page 4 of 7.

Karthik said:   1 decade ago
First pipe fills 3 times faster than second one so x=3x
If together the two pipes can fill the tank in 36 minutes so x*3x=36
x=36/3x
x=12/x
x=144

Manoj said:   1 decade ago
So simple,

Time=work/capacity,

So total capacity=1/x+3/x.

And total work=1.

So total time taken by both of them=36=1/(1/x+3/x).

Pranathi said:   1 decade ago
Why cant we take 3x for faster pipe and x for slower pipe? if I take in that way im getting answer as 9. Is it right or wrong?.

Kant said:   1 decade ago
Let the volume b unit meter cube
so rate of individual filling = rate of combine fillin
so
1/X +1/(X/3) = 1/36
so x=144

Ahammed riyas said:   1 decade ago
If we take x+x/3 instead of 1/x+3/x we cannot get answer because the method of solving will be more complicated.

Anil kumar said:   1 decade ago
If slower pipe is x. Than faster 3x. Take both 36 min. means x = 9 let 9+3 = 12 and 12 square = 144.

Anusha said:   1 decade ago
its simple ya , one pipe =1/x;
anther pipe =3/x:
=4x36 sec=144.

comment pls.

Senthil said:   1 decade ago
Why can't we take x+3x=36 and why we are taking 1/x+3/x=1/36 explain this solution in detail?

Sameer sharma said:   1 decade ago
If a is times faster then b and takes less minutes then in how many time they will fill tank.

Teju M.B said:   1 decade ago
@Laxman:.

Your way of approaching to the problem is good, simple and understandable.


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