Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 8)
8.
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
1 hour
2 hours
6 hours
8 hours
Answer: Option
Explanation:

Let the cistern be filled by pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1 + 1 = 1
x (x + 6) 4

x + 6 + x = 1
x(x + 6) 4

x2 - 2x - 24 = 0

(x -6)(x + 4) = 0

x = 6.     [neglecting the negative value of x]

Discussion:
18 comments Page 2 of 2.

Ajay said:   8 years ago
How x2-2x-24= (x-6) (x+4)? Please explain.

Neha said:   9 years ago
Please explain it.

Kishan said:   9 years ago
Good explanation @Rashmibs.

Achal Kalpande said:   9 years ago
A x x+6 u/m.
B x+6 x u/m.

LCM = x(x + 6).
x(x + 6)/(x + 3) = 8.
Now put values in options in x.
When both sides equate, we get x = 6.

Anshul said:   9 years ago
Pipe B takes 6 hours more than Pipe A to fill the same tank so x+6 for pipe B.

Nirmala Devi said:   9 years ago
How x + 6? Explain.

ABDULLAH said:   9 years ago
@Aman.

Because we have to obtain work done in one hour and we have to find the total time to complete a full work by A or B.

Aman said:   1 decade ago
Why we reciprocal the equation?


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