Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 8)
8.
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
1 hour
2 hours
6 hours
8 hours
Answer: Option
Explanation:

Let the cistern be filled by pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1 + 1 = 1
x (x + 6) 4

x + 6 + x = 1
x(x + 6) 4

x2 - 2x - 24 = 0

(x -6)(x + 4) = 0

x = 6.     [neglecting the negative value of x]

Discussion:
18 comments Page 1 of 2.

Rohit said:   1 decade ago
How to solve x+6+x/x(x+6)-1/4. to form equation. Please tell me the steps..

Shivam said:   1 decade ago
4(2x+6) = x2+6x
0=-24-2x+x2
x2-2x-24 = 0
(x-6)(x+4) = 0

x=6 or x =-4
(1)

RashmiBs said:   1 decade ago
A+B's 1 hours work = 1/4.

B's 1 hours work = 1/6.

First let us find out the B's Part = (1/6)-(1/4).

This is actual B's part of work = 1/12.

Now, find actual A's part = new value of B-(A+B).

= (1/12) - (1/4).

= 2/12 = 1/6 = 6 Hours.
(8)

Aman said:   1 decade ago
Why we reciprocal the equation?

ABDULLAH said:   9 years ago
@Aman.

Because we have to obtain work done in one hour and we have to find the total time to complete a full work by A or B.

Nirmala Devi said:   9 years ago
How x + 6? Explain.

Anshul said:   9 years ago
Pipe B takes 6 hours more than Pipe A to fill the same tank so x+6 for pipe B.

Achal Kalpande said:   9 years ago
A x x+6 u/m.
B x+6 x u/m.

LCM = x(x + 6).
x(x + 6)/(x + 3) = 8.
Now put values in options in x.
When both sides equate, we get x = 6.

Kishan said:   9 years ago
Good explanation @Rashmibs.

Neha said:   9 years ago
Please explain it.


Post your comments here:

Your comments will be displayed after verification.