Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 6 of 8.
Bibhuti Bhusan Swain said:
7 years ago
@Lalli.
When 1/30+1/20+1/10 add up they give 11/60.
When 1/30+1/20+1/10 add up they give 11/60.
Jothi said:
8 years ago
1 =? =>7*3/2=21/2hrs.
Please explain in detail.
Please explain in detail.
Nishant said:
9 years ago
Why we reciprocal 11/20?
Please tell the answer.
Please tell the answer.
Mohsin said:
8 years ago
Why made reciprocal of 11/20? please explain it.
Satya said:
6 years ago
Why made reciprocal of 11/20? Please explain it.
(2)
Lalitha said:
1 decade ago
If 1/30,1/20,1/10 added we get 3/60 how 11/60 ?
Rakesh k said:
1 decade ago
Is there any shortcuts to find pipes problems?
Sailumukund said:
1 decade ago
Any more short cuts in commercial mathematics.
Zara said:
8 years ago
The section is the great help for me. Thanks.
Angel said:
1 decade ago
How 3/10 came ? Please explain it in detail.
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