Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
5
11
6
11
7
11
8
11
Answer: Option
Explanation:

Part filled by (A + B + C) in 3 minutes = 3 1 + 1 + 1 = 3 x 11 = 11 .
30 20 10 60 20

Part filled by C in 3 minutes = 3 .
10

Required ratio = 3 x 20 = 6 .
10 11 11

Discussion:
75 comments Page 5 of 8.

Nishant said:   9 years ago
Why we reciprocal 11/20?

Please tell the answer.

Sadia said:   9 years ago
Can anybody share the simple method for this question?

Archisha said:   9 years ago
@Drishti Anand.

In the end, we are doing (3/10) / (11/20).
Which is equal to (3/10) * (20/11)
That's why we take it in reciprocal.
(1)

Drishti Anand said:   9 years ago
Why they took the reciprocal of 11/20 in final step?

Sujohn rayamajhi said:   10 years ago
Why C's filling is counted twice? Once in total and then individually.

Xyz said:   10 years ago
Please give some simple explanation. Please tell me how to calculate LCM? I forgot it.

Anand said:   1 decade ago
Percentage filled by A in 3 minute = 100x3/30.....1.

Percentage filled by B in 3 minute = 100x3/20.....2.

Percentage filled by C in 3 minute = 100x3/10.....3.

= 3/(1+2).

Sachin said:   1 decade ago
Why divided 3/10 by 11/60?

G.Nandhini said:   1 decade ago
Proportion of are in the tank = Amount of are filled by Tap C in 3 min/Total amount of P, Q, are filled by Taps A, B, C for 3 mins.

Shubha sahu said:   1 decade ago
Please tell me if there is any shortcut to solve this questions?


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