Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
72 comments Page 2 of 8.
Vengatesh said:
1 decade ago
How is 11/60? from where this 11 came from? please explain.
Srinivasan said:
1 decade ago
1/30 + 1/20 + 1/10 = {(2*1)+(3*1)+(6*1)}/60
= 11/60
do L.C.m Now add this, we'ii got wht u wnt...
It's simple........
= 11/60
do L.C.m Now add this, we'ii got wht u wnt...
It's simple........
Aks said:
1 decade ago
How 3/10 came? means 10 came from where?
M@n> said:
1 decade ago
Why should we multiply 3 with a b and c i.e 3*(1/30+1/20+1/10) ?
Lalitha said:
1 decade ago
If 1/30,1/20,1/10 added we get 3/60 how 11/60 ?
Rajthilak said:
1 decade ago
@Sumanth Gowda thanks I understand now.
Sashank singh said:
1 decade ago
A, B and C can fill a tank in 6 hrs. After 2 hrs C is stopped. Then A and B together fill the tank in 7 hrs.
How much C will take individully take to fill the tank?
How much C will take individully take to fill the tank?
Deepi said:
1 decade ago
Hi Sashank Singh
Let me explain in detail.
(A,B and C)Three pipes work together 2 hours from that completed work is
(1/6)*2=1/3
The remaining work is 2/3.
This 2/3 work is done by A and B alone 7hrs.
That is
2/3 =7hrs
1 =? =>7*3/2=21/2hrs
A,B&c=6hrs
A&B=21/2hrs
lets take A,B&C total work time is X and A,B work time is Yhrs.
To find A alone use the formula as (X*Y)/(Y-X)
(6*21/2)/(21/2-6)=14
Let me explain in detail.
(A,B and C)Three pipes work together 2 hours from that completed work is
(1/6)*2=1/3
The remaining work is 2/3.
This 2/3 work is done by A and B alone 7hrs.
That is
2/3 =7hrs
1 =? =>7*3/2=21/2hrs
A,B&c=6hrs
A&B=21/2hrs
lets take A,B&C total work time is X and A,B work time is Yhrs.
To find A alone use the formula as (X*Y)/(Y-X)
(6*21/2)/(21/2-6)=14
Sailumukund said:
1 decade ago
Any more short cuts in commercial mathematics.
Shakthi said:
1 decade ago
Hi,
Please any one check whether my solution is right?
'A' fills tank =30 mins.
'B' fills tank =20 mins.
'C'fills tank =10 mins.
So if we find the LCM for this means we'll assume it as our tanks capacity,
Here its LCM is 60
The tanks capacity is 60 litres
A' fills d tank= 2 lit/min
B' fills d tank=3 lit / min
C' fills d tank=6 lit / min
(A+B+C)'s fill d tank = 11 lit/min
A , B , C respectively discharge P,Q,R respectively
So C it self discharge 6/11 lit
Please any one check whether my solution is right?
'A' fills tank =30 mins.
'B' fills tank =20 mins.
'C'fills tank =10 mins.
So if we find the LCM for this means we'll assume it as our tanks capacity,
Here its LCM is 60
The tanks capacity is 60 litres
A' fills d tank= 2 lit/min
B' fills d tank=3 lit / min
C' fills d tank=6 lit / min
(A+B+C)'s fill d tank = 11 lit/min
A , B , C respectively discharge P,Q,R respectively
So C it self discharge 6/11 lit
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