Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
5
11
6
11
7
11
8
11
Answer: Option
Explanation:

Part filled by (A + B + C) in 3 minutes = 3 1 + 1 + 1 = 3 x 11 = 11 .
30 20 10 60 20

Part filled by C in 3 minutes = 3 .
10

Required ratio = 3 x 20 = 6 .
10 11 11

Discussion:
72 comments Page 2 of 8.

MOHAMMED KHAN SABBIR said:   5 years ago
Solution:

A = 30.
B = 20.
C = 10.
LCM = 60.
A:B:C = 2:3:6.

REQUIRED TIME FOR (A+B+C) = 60/11,
REQUIRED TIME FOR C = 60/6 = 10,
RATIO = (6O/11)/10 = 6/11.
(7)

Deepanshu Sharma said:   5 years ago
@Satya.

Initially, we calculate as per pipe and for total, we need to do reciprocal.

Satya said:   5 years ago
Why made reciprocal of 11/20? Please explain it.
(2)

Abey said:   6 years ago
How 3/10? Please explain.

Rohit said:   6 years ago
LCM of 20,30 and 60 are but ratio 3,2 and 1 and their lcm is 6 which is diveded as by 2,3,6 respectively. Now sum is 11 and after 3 minutes q {3} 3+3 =6 /11

Guruprasad R said:   6 years ago
How 11/60? please explain.

Amit ravanak said:   7 years ago
How 6/11?

Please explain in detail.

Anitha said:   7 years ago
C spend max time 10 minutes.
So, 3/10 minutes.
(3/10)*(20/11).
6/11.

Shailesh Vishwakarma said:   7 years ago
A = 30min fill 100%.
B = 20min fill 100%.
C = 10min fill 100%.

if 3 min filling done all together then,
A =3min fill 10%,
B =3min fill 15%,
C =3min fill 30%.

P =10%,
Q = 15%,
R = 30%.

Total = 55% total tank filled.

Proportion of soln R in total liquid,
=R/Total,
=30/55,
=6/11.
(1)

Vignes R said:   7 years ago
If pipe c is empty the tank. Put negative sign Why use + sign?
(1)


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