Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 2 of 8.
Nandeesh said:
4 years ago
3/30 + 3/20 + 3/10.
(6+9+18)/60 = 33/60 = 11/20,
(3/10)/11/20 = (3/10*20/11) = 6/11.
(6+9+18)/60 = 33/60 = 11/20,
(3/10)/11/20 = (3/10*20/11) = 6/11.
(14)
Aman Kumar said:
5 years ago
According to me,
30, 20, 10 LCM 60 means per unit of each pipe is;
2, 3, 6 total unit = 11.
We can write this way also 60\11 *3\10 = 6\11.
30, 20, 10 LCM 60 means per unit of each pipe is;
2, 3, 6 total unit = 11.
We can write this way also 60\11 *3\10 = 6\11.
(11)
Mruthyunjaya bm said:
5 years ago
Filled by C in 3 minutes = 3/10.
Filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20.
As they told A B C proportional to P Q R (R=C).
Required ratio = chemical solution R in tank/ total chemical solution in tank.
i.e. (3/10)/(11/20),
=(3/10)*(20/11),
= (3*20)/(10*11),
= 60/110,
= 6/11.
Filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20.
As they told A B C proportional to P Q R (R=C).
Required ratio = chemical solution R in tank/ total chemical solution in tank.
i.e. (3/10)/(11/20),
=(3/10)*(20/11),
= (3*20)/(10*11),
= 60/110,
= 6/11.
(8)
MOHAMMED KHAN SABBIR said:
5 years ago
Solution:
A = 30.
B = 20.
C = 10.
LCM = 60.
A:B:C = 2:3:6.
REQUIRED TIME FOR (A+B+C) = 60/11,
REQUIRED TIME FOR C = 60/6 = 10,
RATIO = (6O/11)/10 = 6/11.
A = 30.
B = 20.
C = 10.
LCM = 60.
A:B:C = 2:3:6.
REQUIRED TIME FOR (A+B+C) = 60/11,
REQUIRED TIME FOR C = 60/6 = 10,
RATIO = (6O/11)/10 = 6/11.
(7)
Deepanshu Sharma said:
5 years ago
@Satya.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Satya said:
6 years ago
Why made reciprocal of 11/20? Please explain it.
(2)
Abey said:
6 years ago
How 3/10? Please explain.
Rohit said:
6 years ago
LCM of 20,30 and 60 are but ratio 3,2 and 1 and their lcm is 6 which is diveded as by 2,3,6 respectively. Now sum is 11 and after 3 minutes q {3} 3+3 =6 /11
Guruprasad R said:
7 years ago
How 11/60? please explain.
Amit ravanak said:
7 years ago
How 6/11?
Please explain in detail.
Please explain in detail.
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