Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 9)
9.
Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
Answer: Option
Explanation:
| Part filled by A in 1 min = | 1 | . |
| 20 |
| Part filled by B in 1 min = | 1 | . |
| 30 |
| Part filled by (A + B) in 1 min = |  |
1 | + | 1 |  |
= | 1 | . |
| 20 | 30 | 12 |
Both pipes can fill the tank in 12 minutes.
Discussion:
15 comments Page 2 of 2.
Animesh Sharma said:
9 years ago
Two pipes A and B can fill a tank in 45 and 30 hours respectively. If both the pipes are used together, then how long will it take to fill the tank?
Solve this problem.
Solve this problem.
(1)
Rajesh said:
9 years ago
@Animesh.
(45 + 30) = 75, (45 * 30) = 1350.
75/1350,
= 1/18.
Answer: 1/18.
(45 + 30) = 75, (45 * 30) = 1350.
75/1350,
= 1/18.
Answer: 1/18.
Naresh said:
8 years ago
In AB/A+B format 30 * 20/20 + 30 = 600/50 = 12.
(2)
Kailash Sharma said:
7 years ago
a=20;
b=30;
l.c.m of 20,30=60;
a's=60/20 =>3;
b's=60/30 =>2;
a+b=60/5 =>12.
b=30;
l.c.m of 20,30=60;
a's=60/20 =>3;
b's=60/30 =>2;
a+b=60/5 =>12.
(4)
Jamshaid said:
3 years ago
Tank filled in 4 min = 4 * (1/15+1/20) = 28/60,
Remaining = 32/60.
Time for remaining by B = 32/60 / 1/20 = 32*20/60 = 10.2/60.
Remaining = 32/60.
Time for remaining by B = 32/60 / 1/20 = 32*20/60 = 10.2/60.
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