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Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 1)
Permutation and Combination
1.
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
564
645
735
756
None of these
Answer: Option
Explanation:

We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).

Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
= 7 x 6 x 5 x 6 x 5 + (7C3 x 6C1) + (7C2)
3 x 2 x 1 2 x 1
= 525 + 7 x 6 x 5 x 6 + 7 x 6
3 x 2 x 1 2 x 1
= (525 + 210 + 21)
= 756.

Discussion:
137 comments Page 12 of 14.
Abhishek said:   1 decade ago
Is any shortcut solution of above question?
Shay tee said:   1 decade ago
Okay. How are 7c3 and 7c4 both equal to 35?
Riya said:   8 years ago
I did not understand how we got 21 for 7C5?
(1)
Sneha said:   8 years ago
Any one know the another method of solving?
(1)
Abi said:   3 years ago
Anyone, Please explain this 7C3 * 6C1+7C2.
(11)
Adith said:   1 year ago
Thanks everyone for explaining the answer.
(7)
Osei-tutu said:   1 decade ago
Please what is mean by 7C3. Please help.
Priyanka Das said:   1 decade ago
7C2 means 2 men are selected from 7 men.
Kanaga said:   1 decade ago
Which formula using this method clearly?
Vamsi mvk said:   7 years ago
@Pavz.

Thanks for your explanation.
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