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Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 1)
Permutation and Combination
1.
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
564
645
735
756
None of these
Answer: Option
Explanation:

We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).

Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
= 7 x 6 x 5 x 6 x 5 + (7C3 x 6C1) + (7C2)
3 x 2 x 1 2 x 1
= 525 + 7 x 6 x 5 x 6 + 7 x 6
3 x 2 x 1 2 x 1
= (525 + 210 + 21)
= 756.

Discussion:
137 comments Page 14 of 14.
Kranthi said:   1 decade ago
How 7C4 became 7C3 ?
Siva kumar said:   9 years ago
Nice solution @Nagu.
Tshewang chophel said:   8 years ago
How to get 7c3=35?
Teja said:   7 years ago
Here, ncr=nc(n-r).
Kumar said:   1 decade ago
Nice answer nagu.
Felix said:   8 years ago
How is 7c3 = 35?
Rishi said:   1 decade ago
How 7c3= 35 ?
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