Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option
Explanation:
| Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = |  |
7 x 6 | x 3 |  |
= 63. |
| 2 x 1 |
Discussion:
51 comments Page 4 of 6.
Kavu said:
1 decade ago
(7C2 x 3C1) = (7/2 x 6/1) x 3= 63.
How it comes?
How it comes?
Naresh said:
9 years ago
How to get the answer? Please anybody explain me.
(1)
Manju said:
1 decade ago
nCr = n!/(n-r)!r!
= 7C5*3C2.
= (7*6/2*1)*3 = 63.
= 7C5*3C2.
= (7*6/2*1)*3 = 63.
Mariyam said:
9 years ago
@Satish your explanation is very understandable.
Karthik said:
1 decade ago
Why can't we multiply 7C5 nd 3C2 directly ?
Bhavani said:
7 years ago
How will get 7c2* 3c1?
Please explain me.
Please explain me.
Mike said:
7 years ago
Where 6 comes from? Please explain me.
BGT said:
1 decade ago
How can't we use any other e example?
Priya said:
2 decades ago
How? I can't understand this problem.
Shree said:
7 years ago
Thanks for giving an explanation.
(2)
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