Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option
Explanation:
| Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = |  |
7 x 6 | x 3 |  |
= 63. |
| 2 x 1 |
Discussion:
51 comments Page 5 of 6.
Chandan said:
1 decade ago
Why multiplication not addition?
Shivaraj said:
9 years ago
@Feze.
3c1=3 By std formulae.
3c1=3 By std formulae.
Sudha said:
9 years ago
How 7c2 will come instead 7C5?
Feze said:
9 years ago
Why we multiply with 3 here?
Shital said:
1 decade ago
I didn't understand 7c2*3c1.
Keerthana said:
7 years ago
The answer is 63. I agree.
(2)
Amanat said:
5 years ago
Thank you so much @Satish.
(1)
Kyosi billy said:
8 years ago
Thanks for explaining it.
Divya said:
1 decade ago
How 3c2 change into 3c1?
Binushree said:
1 decade ago
How to multiply?
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