Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option
Explanation:
| Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = |  |
7 x 6 | x 3 |  |
= 63. |
| 2 x 1 |
Discussion:
51 comments Page 3 of 6.
Jat said:
1 decade ago
(7C5 x 3C2) = (7C2 x 3C1)
This step i can't understand.
Please explain me.
This step i can't understand.
Please explain me.
Manasa said:
1 decade ago
@jat
its just formula
n =n
c c
r n-r
n=7,r=5
7C5=7C2
its just formula
n =n
c c
r n-r
n=7,r=5
7C5=7C2
SHIVAM SHUKLA said:
10 years ago
I didn't understand this problem. Please each and every step explain it.
Anoushka said:
9 years ago
Sir I haven't understood why have we multiplied 3 with 7*6/2*1 *3.
Nirmal said:
1 decade ago
(7C2 x 3C1) = 7 x 6 x 3
How it happened explain please?
How it happened explain please?
ACHUTHARAJ said:
1 decade ago
Basic formula nCr = nCn-r
so 7C7-5 = 7C2
3C3-2 = 3C1
so 7C7-5 = 7C2
3C3-2 = 3C1
Harish julai said:
10 years ago
Hello @Sravani.
If n>r, then ncr becomes nc(n-r).
If n>r, then ncr becomes nc(n-r).
Pooja said:
1 decade ago
I understood that thanks! we have to use nCr=nCn-r.
Vishesh said:
1 decade ago
Same here what is this c? I don't understand this.
Sam said:
9 years ago
Why we are taking as 7c2 * 3c1? Please explain it.
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