Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
63
90
126
45
135
Answer: Option
Explanation:

Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = 7 x 6 x 3 = 63.
2 x 1

Discussion:
51 comments Page 4 of 6.

Suvarna said:   1 decade ago
It takes more time to calculate 7c5 than 7c2& 3C2 than 3C1, to improve the speed we are doing like this.

Jat said:   1 decade ago
(7C5 x 3C2) = (7C2 x 3C1)
This step i can't understand.
Please explain me.

Manasa said:   1 decade ago
@jat
its just formula
n =n
c c
r n-r
n=7,r=5
7C5=7C2

Zalak said:   1 decade ago
(7C5 x 3C2) = (7C2 x 3C1)

This step I can't understand. Please explain me.

Kavu said:   1 decade ago
(7C2 x 3C1) = (7/2 x 6/1) x 3= 63.

How it comes?

ACHUTHARAJ said:   1 decade ago
Basic formula nCr = nCn-r
so 7C7-5 = 7C2
3C3-2 = 3C1

Divya said:   1 decade ago
How 3c2 change into 3c1?

Ankur anand said:   1 decade ago
Why combination why not permutation ?

Similar as that of the arranging of letters the people are diffrent so there can be many ways by permutation.

Nirmal said:   1 decade ago
(7C2 x 3C1) = 7 x 6 x 3

How it happened explain please?

BGT said:   1 decade ago
How can't we use any other e example?


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