Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option
Explanation:
Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = | ![]() |
7 x 6 | x 3 | ![]() |
= 63. |
2 x 1 |
Discussion:
51 comments Page 6 of 6.
Priya said:
2 decades ago
How? I can't understand this problem.
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