Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 11)
11.
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option
Explanation:
| Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = |  |
7 x 6 | x 3 |  |
= 63. |
| 2 x 1 |
Discussion:
51 comments Page 3 of 6.
Feze said:
9 years ago
Why we multiply with 3 here?
Jyoti said:
9 years ago
According to me, the final answer which displayed is wrong.
If we multiply 126 is coming.
If we multiply 126 is coming.
Shivaraj said:
9 years ago
@Feze.
3c1=3 By std formulae.
3c1=3 By std formulae.
Kyosi billy said:
8 years ago
Thanks for explaining it.
Bhavani said:
7 years ago
How will get 7c2* 3c1?
Please explain me.
Please explain me.
Mike said:
7 years ago
Where 6 comes from? Please explain me.
Teja said:
1 decade ago
Hey see you said that 7c5*3c2 is long procedure. That the thing we take ncr formula. ?and second thing why we take that formula in this problem? am not?
Sahithya said:
1 decade ago
Hi priya,.
We have to select 5men out of 7 men, this can be done in 7C5 ways
= 7C2 [Ref: nCr=nC (n-r) ].
And also we hav to select 2women out of 3 women, this can be done in 3C2 ways = 3C1.
As these two combinations are compulsry, we hav to multiply 7C2 and 3C1.
I think you understand.
We have to select 5men out of 7 men, this can be done in 7C5 ways
= 7C2 [Ref: nCr=nC (n-r) ].
And also we hav to select 2women out of 3 women, this can be done in 3C2 ways = 3C1.
As these two combinations are compulsry, we hav to multiply 7C2 and 3C1.
I think you understand.
Binushree said:
1 decade ago
How to multiply?
Karthik said:
1 decade ago
Why can't we multiply 7C5 nd 3C2 directly ?
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