Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
 Required number of ways = |
6! | = 360. |
| (1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 7 of 9.
Vamshi said:
8 years ago
They didn't ask without repetition? Then why you divided by 2?
Yusuf said:
1 decade ago
Why not sometime division and sometime by considering vowel?
Paulvannan said:
9 years ago
Hi factorial value is 1*2*36*4*5*6* = 720.
So 720/2 = 360.
So 720/2 = 360.
Anandavalli said:
7 years ago
But E and A are vowels so we have to take it as 1, right?
(1)
Neeraj said:
1 decade ago
Hmm Krishna you are right. I got the answer by your way.
Sonu said:
1 decade ago
Ritu explain it in a very gooo way thanks a lot ritu.
Divya said:
9 years ago
@Savitri.
It is;
L = 1.
E = 2.
A = 1.
D = 1.
R = 1.
It is;
L = 1.
E = 2.
A = 1.
D = 1.
R = 1.
Reena said:
1 year ago
Why not consider it as 5!?
Please explain to me.
Please explain to me.
(2)
Ezaz Ahmed said:
8 years ago
Thanks for giving the explanation of the answer.
Savitri said:
9 years ago
(1!)(2!)(1!)(1!)(1!)
How it is? Explain me.
How it is? Explain me.
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