Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
![]() |
6! | = 360. |
(1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 6 of 9.
Vinny said:
1 decade ago
LEADER contains 6 letters.
So 2 are similar letters.
Therefore 6!/2!=360.
So 2 are similar letters.
Therefore 6!/2!=360.
Savitri said:
9 years ago
@Sundar, Can you please explain this, how it is 72?
= 5! - 4! x 2!.
= 72.
= 5! - 4! x 2!.
= 72.
Harish said:
1 decade ago
In how many different way can the letters of the word CREAM arranged.
Kuldip said:
1 decade ago
Can anybody explain me when permutation & when combination used?
Joykhwaka said:
1 year ago
Why are they not treating vowels separately? Anyone please explain.
(3)
Yaswanth said:
6 years ago
LEADER consist of 6 words,
In that 2E's so,
6!/2! = 720/2 = 360.
In that 2E's so,
6!/2! = 720/2 = 360.
(1)
Pavan kalyan said:
1 decade ago
Yes friends answer 360 is correct because E is repeated 2 times.
Raj Kumar said:
6 years ago
The answer is 360 because here in question 'e' is coming twice.
(3)
Manish said:
8 years ago
7 letters out of which 2 letters are repeated.
Therefore 7!/2!
Therefore 7!/2!
Aswathy said:
7 years ago
Hi, I am not getting this, Please explain this answer clearly.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers