Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
 Required number of ways = |
6! | = 360. |
| (1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 1 of 9.
Reena said:
1 year ago
Why not consider it as 5!?
Please explain to me.
Please explain to me.
(2)
Joykhwaka said:
1 year ago
Why are they not treating vowels separately? Anyone please explain.
(3)
Sandeep Bodamwad said:
4 years ago
Yes, the answer 360 is very correct, because there letter E is repeated. So the whole letters count will be 5. 1+2+3+4+5+ = 360
(1)
Rasi said:
4 years ago
Hey guys!
LEADER = 6! =720
(E E) = 2! = 2
Now divide,
720/2 = 360.
Now it is clear right?
LEADER = 6! =720
(E E) = 2! = 2
Now divide,
720/2 = 360.
Now it is clear right?
(26)
Yaswanth said:
6 years ago
LEADER consist of 6 words,
In that 2E's so,
6!/2! = 720/2 = 360.
In that 2E's so,
6!/2! = 720/2 = 360.
(1)
Julius said:
6 years ago
In how many ways can the word obasanjo be arranged so that the vowels will never come together.
(4)
Raj Kumar said:
6 years ago
The answer is 360 because here in question 'e' is coming twice.
(3)
Yuvraj k said:
7 years ago
I think the Answer is 720.
Aswathy said:
7 years ago
Hi, I am not getting this, Please explain this answer clearly.
(1)
Anandavalli said:
7 years ago
But E and A are vowels so we have to take it as 1, right?
(1)
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