Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 12)
12.
How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?
40
400
5040
2520
Answer: Option
Explanation:

'LOGARITHMS' contains 10 different letters.

Required number of words = Number of arrangements of 10 letters, taking 4 at a time.
= 10P4
= (10 x 9 x 8 x 7)
= 5040.

Discussion:
68 comments Page 5 of 7.

Shashwat said:   1 decade ago
Why permutation is used explain?

Vini said:   1 decade ago
Logarithms===> total= 10 alphabets.. okay
we have to form 4-letter words, without repeating the letters.
_ _ _ _
we have place for 4 alphabets
In 1st blank, out of 10, any1 of it can come,so we have 10 choices--->10
In 2nd blank, now,9 letters are left, out of 9 u can choose one---->10*9
In 3rd blank, now 8 left, i.e.--->10*9*8
In 4th blank, any remaining of 7 letters can come---> 10*9*8*7
= 5040

Preethi said:   1 decade ago
Why we used permutations here and why not combinations.
Please explain clearly when we use npr and when we use ncr.

Vaishali.n said:   1 decade ago
How to know whether to use permutation or combination?

Sathya said:   1 decade ago
Permutation = when ordering is considered.
(means here to form a word ordering is important).

Whereas in
Combination - ordering is not considered.

Hansh said:   1 decade ago
Why you have used permutation here? please tell me the repetions of 4 letters concept?

Kuldeep vijay said:   1 decade ago
Yes, when repetitions not allowed it is an ordering condition.

Mini said:   1 decade ago
The formula we hv usd here is = n!/(P1!)(P2!)...(Pr!)
Here n=10(no. of letters) and P1,P2.. are the different letters of the word.
Then the no. of permutation of these 10 letters is
= 10!/(1!)(1!)..upto 10th letter [(1!)...upto 10th letter used bcoz each letter occured only once]
= 10*9*8*7 [bcoz we hv to make 4 letter words]
= 5040

AISH said:   1 decade ago
If position of word matter (no repetition allowed) Then we have to use permutation.

And if no position matter we have to use combination.

Chandani said:   1 decade ago
When we form LOGA and AGOL it is permutation but in combination we don't write like r, s is similar to s, r -in combination, not in permutation. So in above question we are not allowed to double the letter but are allowed to use the same letter in different words. .


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