Aptitude - Percentage - Discussion

@Deepesh.

Why it is not so because, if the given expression is not given then it is not possible to determine, but it is clearly given na that's why we can't say answer C.

I even don't understand the question.

In such cases always assume some value for x and y.

Let x = 100 and y = 100. (Note-always assume value which is divisible by denominator).

Now A = x%y.

A = x/100*y, but we substitute the assumed value of x and y.

A = 100/100*100 (x = 100, y = 100 assumed value).

You will get:

A = 100.

Now move to next part.

B = y%x.

B = x/100*y, but we again substitute the assumed value of x and y.

B = 100/100*100 it will give you.

B = 100.

Now A = 100 and B = 100 therefore you can say that A = B.

@Abhi.

10% of 100 is 10 only not 90, if it is 10% lower by 100 then it is 90.

I agree with @Mala, Why C is not the correct answer? Even I got the answer A = B.

In a club 40% of the members were female. 40 new male became a member of the club and as a result, the percent of female members dropped to 30%. How many females member are there in the club now?

Can anyone solve this?

Amar, Anoop, and Aparna shared a certain amount among themselves such that Amar gets 20% more than Anoop and Anoop get 20% more than Aparna. Aparna got Rs 176 less than Amar. How much amount did Anoop get?

Can anyone solve this?

And, I did understood problem no. 5.

I think 160 females.

I didn't understand the problem. So please clarify me.