Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 16 of 17.
Borra vamsi krishna said:
9 years ago
Please explain in simple way.
Dsr said:
7 years ago
Good explanation, Thanks all.
Raveesh r said:
5 years ago
42+33 = 75.
42/75*100 = 56%.
42/75*100 = 56%.
Debasis Biswas said:
1 decade ago
Correct answer is 42, 33.
Vasu said:
7 years ago
How it is 56-44/100=12?
Ramana said:
6 years ago
Why we add x and x+9?
DURGAO said:
9 years ago
Thank you @ Radhika.
Nagesh v said:
7 years ago
Thank you @Shrikant.
Lingeswaran said:
8 years ago
Thanks @Aman Tomar.
Chandan pandit said:
10 years ago
Please clear this.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers