Aptitude - Percentage - Discussion

Thank you @Ramesh.

My answer is 120.

Because, there is no condition like,

No.of students(age>8) = (2/3) * no.of students (age=8).

Its more like:
No.of students(age>8) = no.of students (age=8),

So,
80% of students =(age>8)+(age=8) =48+48=96,
100% of students = 96/0.8 = 120.

Well said, thanks @Priyanka.

Thanks @Robin Loomba.

Under these question, three categories have come i.e,

1. Less than 8 years aged students(A)
2. exact 8 years aged students(C)
3. Greater than 8 years students.(B)

Total no. of students (x) = A+B+C.

We know C=48 no,
From question A= 20%x,
and Remaining B&C=100-20,
=80%.

Then (80/100)x= C+(2/3)C (Where B=(2/3) of C),
(80/100)X= 48+(2/3)48.

By Resolving this X=100 is the answer.

Well said @Showry.

Thanks for explaining the solutions.

Thank you @Ramesh.

Why 8 years of students = 2/3 of 48? Please explain.

Let a total number of the student be 100% out of which 20% of students are below 8years of age so remaining 80% of students are either 8years of age or above 8years of age.

No of students of 8years age=48(given)


No of students above 8years age=2/3* no of students of 8years age
= 2/3*48,
= 32.

80% of students= no of students of 8years age + no of student above 8years age.
80% of students=48+32,
=80.
(We have to find total students in the school so)

100% of students=80/80*100.
=100.

Total number of students in the school are 100.