Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
78 comments Page 4 of 8.
Vishnu pareek said:
8 years ago
x=120%of y
x=120/100of y
x=6/5 of y
total=5+6=11 then y=5
So y=5/11*550 = 250.
x=120/100of y
x=6/5 of y
total=5+6=11 then y=5
So y=5/11*550 = 250.
Naveed said:
8 years ago
x + y = 550 ......... (1).
x = 120% y.
x = 120 / 100 y = 1.2 y ...... (2).
Put in Equation 2 in 1,
1.2 y + y = 550.
2.2 y = 550.
y = 550 / 2.2 = 250.
x = 120% y.
x = 120 / 100 y = 1.2 y ...... (2).
Put in Equation 2 in 1,
1.2 y + y = 550.
2.2 y = 550.
y = 550 / 2.2 = 250.
Priyanka said:
8 years ago
Thanks for your solution @Girish.
Rohan said:
8 years ago
Thanks @Lalit.
Aru said:
8 years ago
Here its not mentioned that X earns 120%Y PER WEEK. Can answer be "none of these"?
Gopi said:
7 years ago
Excellent, Thanks @Girish.
GOWTHAM said:
7 years ago
Total X+Y=550rs,
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
Suresh said:
7 years ago
Thanks @Ashok.
Balaji said:
7 years ago
Good explanation @Ramesh.
Ram's power said:
7 years ago
@All.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
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