Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
78 comments Page 4 of 8.
Krishn said:
6 years ago
X is gaining 20% more than y.
X ------> Y
5 ------> 6.
5 + 6 = 11.
11>>>>>550.
1 >>>>>>50.
5 >>>>>>250.
( 6 is 120% of 5).
X ------> Y
5 ------> 6.
5 + 6 = 11.
11>>>>>550.
1 >>>>>>50.
5 >>>>>>250.
( 6 is 120% of 5).
Dhamma said:
6 years ago
120:100 = 550 6:5 = 550.
6/11 = 300.
5/11 = 250.
6/11 = 300.
5/11 = 250.
Aswin mohamed said:
7 years ago
Thanks for explaining @Ramesh.
Venu said:
7 years ago
X : Y = 120 : 100 --> 6:5.
Y's pay = (5/11)X550 = 250.
Y's pay = (5/11)X550 = 250.
Santosh said:
7 years ago
Good, thank for explaining @Ramesh.
Madhavi said:
7 years ago
Thanks @Ram.
Parag said:
7 years ago
Thanks @Mini.
Sudarshan G said:
7 years ago
@Ramesh.
Thanks for explaining the solution.
Thanks for explaining the solution.
Ram's power said:
7 years ago
@All.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Balaji said:
7 years ago
Good explanation @Ramesh.
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