Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
144 comments Page 4 of 15.
Kumar said:
7 years ago
3 boundaries = 3*4=12,
8 sixes = 8*6=48,
=> 48+12=60 (runs scored with the help of boundaries),
runs scored by running b/w wickets = 110-60=50,
%runs scored by running = (50/110)*100.
8 sixes = 8*6=48,
=> 48+12=60 (runs scored with the help of boundaries),
runs scored by running b/w wickets = 110-60=50,
%runs scored by running = (50/110)*100.
Aparna said:
1 decade ago
@seshadri,
remember one thing
any fraction can be written in the following format
quotient *(remainder/divisor)
we get fraction as
500/11
just convert it into above format
thats it
remember one thing
any fraction can be written in the following format
quotient *(remainder/divisor)
we get fraction as
500/11
just convert it into above format
thats it
Chandu said:
1 decade ago
800 is how much % of 7200?
800*%/100 = 7200.
By solving we get 800%.
And by using above method.
800/7200*100=11.11111111.
Which will be the correct method and what is the answer.
800*%/100 = 7200.
By solving we get 800%.
And by using above method.
800/7200*100=11.11111111.
Which will be the correct method and what is the answer.
Uday said:
9 years ago
Total score 110.
3 boundaries = (3 * 4) =12.
8 sixes = 8 * 6 = 48.
12 + 48 = 60.
Remaining runs (110 - 60) scored by running.
So % is 50/110 * 100 = 500/11 = option b.
3 boundaries = (3 * 4) =12.
8 sixes = 8 * 6 = 48.
12 + 48 = 60.
Remaining runs (110 - 60) scored by running.
So % is 50/110 * 100 = 500/11 = option b.
Sana said:
7 months ago
See follow like this:
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110-48 + 12 = 50.
Now find
110= 100%.
50=?
50/110 * 100 = 45 5/11.
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110-48 + 12 = 50.
Now find
110= 100%.
50=?
50/110 * 100 = 45 5/11.
(38)
Madhuwala said:
2 years ago
Total run = 110.
Eight sixes = 48 run,
Three boundaries = 12run,
So, running between wicket=(110-48+12) = 50.
therefore, percentage of 50 run =(50/110)*100 = 45 * 5/11.
Eight sixes = 48 run,
Three boundaries = 12run,
So, running between wicket=(110-48+12) = 50.
therefore, percentage of 50 run =(50/110)*100 = 45 * 5/11.
(79)
Aravind Ramamoorthy said:
7 years ago
Runs=110.
(Boundaries)fours = 4 * 3 = 12,
Sixes=8*6=48,
total=48+12=60,
110-60 = 50,
50/110 = 5/11,
5/11*100(%) = 500/11,
45*11= 495,
Balance = 5,
= 45 5/11.
(Boundaries)fours = 4 * 3 = 12,
Sixes=8*6=48,
total=48+12=60,
110-60 = 50,
50/110 = 5/11,
5/11*100(%) = 500/11,
45*11= 495,
Balance = 5,
= 45 5/11.
Vikrant raushan said:
1 decade ago
@Jay. Answer to wheat problem.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Shiva shankar said:
10 years ago
In a fraction, the number is increased by 20% and the denominator is decreased by 10% then the value of the fraction becomes 5/7. Then find the original fraction?
Manisha said:
6 years ago
@Pavan.
Let x be his sales.
6000 salary out of which 1000 is fixed.
So he earns 5000 out of his sales.
10% commission on his sales.
10*x/100 = 5000.
x = 50000.
Let x be his sales.
6000 salary out of which 1000 is fixed.
So he earns 5000 out of his sales.
10% commission on his sales.
10*x/100 = 5000.
x = 50000.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers