Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
144 comments Page 2 of 15.
Pavan said:
8 years ago
Can someone help me in solving the following question?
A salesman gets Rs. 1000Pm. Fixed salary. In addition, he gets 10% commission on his sales, if he wishes to earn a total of Rs. 6000 in a particular month, what should be his sales in the month?
A. Rs. 25000 b. Rs. 4000 c. Rs. 50000 d. Rs. 60000.
Please, someone explain with steps.
A salesman gets Rs. 1000Pm. Fixed salary. In addition, he gets 10% commission on his sales, if he wishes to earn a total of Rs. 6000 in a particular month, what should be his sales in the month?
A. Rs. 25000 b. Rs. 4000 c. Rs. 50000 d. Rs. 60000.
Please, someone explain with steps.
Harish said:
1 decade ago
3 boundaries means 3*4 = 12 runs.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
A SANTHI said:
3 years ago
The total run is - 110
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
(72)
Rajesh.b said:
8 years ago
Total runs he scored = 110.
The scored 3 boundaries and 8 sixes=> 3 * 4 + 6 * 8 = 60,
The runs scored by him running between the wickets => 110 - 60 = 50.
By unitary method,
For 110runs ---------100%
For 50 runs ----------?.
That follows as = 50 * 100/110 = result.
The scored 3 boundaries and 8 sixes=> 3 * 4 + 6 * 8 = 60,
The runs scored by him running between the wickets => 110 - 60 = 50.
By unitary method,
For 110runs ---------100%
For 50 runs ----------?.
That follows as = 50 * 100/110 = result.
Abinav said:
8 years ago
Hi,
3 * 4 + 8 * 6 = 60 runs.
110 runs - 60 = 50 => 50/110 (110 from total runs). 110 = 50
100 = X so 110 times 5/110 = 45 5/11.
3 * 4 + 8 * 6 = 60 runs.
110 runs - 60 = 50 => 50/110 (110 from total runs). 110 = 50
100 = X so 110 times 5/110 = 45 5/11.
Prasanna said:
4 years ago
Total runs : 110
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
(4)
Swayam Rampal said:
7 years ago
The answer given is incorrect. The correct answer is 40%.
Total runs=110.
No. of sixes= 8,
Runs by sixes=6*8=54,
No. of fours=3,
Runs scored by fours=4*3=12,
Runs between the wickets=110-(54+12)=110-66=44,
% runs scored between wickets= (44÷110)*100=40% ans.
Total runs=110.
No. of sixes= 8,
Runs by sixes=6*8=54,
No. of fours=3,
Runs scored by fours=4*3=12,
Runs between the wickets=110-(54+12)=110-66=44,
% runs scored between wickets= (44÷110)*100=40% ans.
Vijay said:
1 decade ago
Total batsman score = 110.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
NIRMAL S said:
4 years ago
The question is very simple.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
(5)
Divya said:
7 years ago
An article is listed at Rs 65. A customer bought this article for Rs 56. 16 with two successive discounts, out of which one is 10%. The other discount of this discount scheme that was allowed by the shopkeeper is?
Can anybody give the answer?
Can anybody give the answer?
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