Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
150 comments Page 2 of 15.
Pavan said:
8 years ago
Can someone help me in solving the following question?
A salesman gets Rs. 1000Pm. Fixed salary. In addition, he gets 10% commission on his sales, if he wishes to earn a total of Rs. 6000 in a particular month, what should be his sales in the month?
A. Rs. 25000 b. Rs. 4000 c. Rs. 50000 d. Rs. 60000.
Please, someone explain with steps.
A salesman gets Rs. 1000Pm. Fixed salary. In addition, he gets 10% commission on his sales, if he wishes to earn a total of Rs. 6000 in a particular month, what should be his sales in the month?
A. Rs. 25000 b. Rs. 4000 c. Rs. 50000 d. Rs. 60000.
Please, someone explain with steps.
Anonymous said:
4 weeks ago
Total Runs 110.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
Harish said:
1 decade ago
3 boundaries means 3*4 = 12 runs.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
A SANTHI said:
3 years ago
The total run is - 110
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
(72)
Bittu Rana said:
2 months ago
Total run = 110.
And runs scored by boundaries and sixes are (3*4=12)+ (8*6=48) = 60,
Rest scores made by running = 110 - 60 = 50 runs.
So percentage of running's score = (running's score / total Score )*100.
= (50/110)*100 = (5/11)*100.
= 500/11,
=> (45/1)+(5/11).
i.e option (B).
And runs scored by boundaries and sixes are (3*4=12)+ (8*6=48) = 60,
Rest scores made by running = 110 - 60 = 50 runs.
So percentage of running's score = (running's score / total Score )*100.
= (50/110)*100 = (5/11)*100.
= 500/11,
=> (45/1)+(5/11).
i.e option (B).
(5)
Rajesh.b said:
9 years ago
Total runs he scored = 110.
The scored 3 boundaries and 8 sixes=> 3 * 4 + 6 * 8 = 60,
The runs scored by him running between the wickets => 110 - 60 = 50.
By unitary method,
For 110runs ---------100%
For 50 runs ----------?.
That follows as = 50 * 100/110 = result.
The scored 3 boundaries and 8 sixes=> 3 * 4 + 6 * 8 = 60,
The runs scored by him running between the wickets => 110 - 60 = 50.
By unitary method,
For 110runs ---------100%
For 50 runs ----------?.
That follows as = 50 * 100/110 = result.
Abinav said:
8 years ago
Hi,
3 * 4 + 8 * 6 = 60 runs.
110 runs - 60 = 50 => 50/110 (110 from total runs). 110 = 50
100 = X so 110 times 5/110 = 45 5/11.
3 * 4 + 8 * 6 = 60 runs.
110 runs - 60 = 50 => 50/110 (110 from total runs). 110 = 50
100 = X so 110 times 5/110 = 45 5/11.
Prasanna said:
4 years ago
Total runs : 110
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
(4)
Swayam Rampal said:
7 years ago
The answer given is incorrect. The correct answer is 40%.
Total runs=110.
No. of sixes= 8,
Runs by sixes=6*8=54,
No. of fours=3,
Runs scored by fours=4*3=12,
Runs between the wickets=110-(54+12)=110-66=44,
% runs scored between wickets= (44÷110)*100=40% ans.
Total runs=110.
No. of sixes= 8,
Runs by sixes=6*8=54,
No. of fours=3,
Runs scored by fours=4*3=12,
Runs between the wickets=110-(54+12)=110-66=44,
% runs scored between wickets= (44÷110)*100=40% ans.
Vijay said:
1 decade ago
Total batsman score = 110.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
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