Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
151 comments Page 10 of 16.
Shivashankar said:
1 decade ago
75% of A=120% of B. By what percent is A more than B ?
Yash said:
1 decade ago
Total 3 boundaries 4*3=12, no.of six 6 = 8 = 48, than total = 60.
And total score is 110, and 110-60 = 50, and 50/110*100 = 45.45.
And total score is 110, and 110-60 = 50, and 50/110*100 = 45.45.
R patel said:
1 decade ago
How 4 and 6 came?
SriShivKeerthy said:
1 decade ago
Total 110-((3*4)+(8*6)) = 110-60 = 50.
50 runs he got only by running between the wickets.
So percentage is (50/110)*100 = 45.5%.
Answer is 45.5%.
50 runs he got only by running between the wickets.
So percentage is (50/110)*100 = 45.5%.
Answer is 45.5%.
Iranna said:
10 years ago
How it divide the 50/110? Please explain?
Sharath said:
10 years ago
@Harish.
Really fantastic and simple explanation.
Really fantastic and simple explanation.
Afrin said:
9 years ago
Why should we write 50/110 * 100?
As my knowledge to get a percentage of 50 in 110 we have to calculate as 50/100 * 110.
As my knowledge to get a percentage of 50 in 110 we have to calculate as 50/100 * 110.
Rahul said:
9 years ago
45 * (5/11)% = 45.45% then why option B and why not option A?
Uday said:
9 years ago
Total score 110.
3 boundaries = (3 * 4) =12.
8 sixes = 8 * 6 = 48.
12 + 48 = 60.
Remaining runs (110 - 60) scored by running.
So % is 50/110 * 100 = 500/11 = option b.
3 boundaries = (3 * 4) =12.
8 sixes = 8 * 6 = 48.
12 + 48 = 60.
Remaining runs (110 - 60) scored by running.
So % is 50/110 * 100 = 500/11 = option b.
Rajasekhar said:
9 years ago
Thank you @Aparna.
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