Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 18)
18.
Which one of the following numbers is exactly divisible by 11?
Answer: Option
Explanation:
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
Discussion:
47 comments Page 4 of 5.
Priyanka P. said:
2 decades ago
@ Ali
No its just for 11..
The difference b/w odd and even numbers total should be 0, 11 or multiple of 11 i.e. 22, 484 etc.
No its just for 11..
The difference b/w odd and even numbers total should be 0, 11 or multiple of 11 i.e. 22, 484 etc.
Shoeb said:
2 decades ago
Good, I like the solution. Thanks Priyanka.
Abhishek Rana said:
1 decade ago
Thanx Priyanka.
Saranya said:
1 decade ago
odd places - even places will not come because for example 4+6+1 is an odd place
Pratiksha sharma said:
1 decade ago
415624/11=37784.
It is exactly divisible by 11. This is easiest method.
It is exactly divisible by 11. This is easiest method.
Vimal said:
1 decade ago
@ pratiksha.
Ya you are right. But in aptitude test, they won't allow you to use calculator!!!
Ya you are right. But in aptitude test, they won't allow you to use calculator!!!
Vidyadhar said:
1 decade ago
Divisibility rule:
Form the alternating sum of the digits.
415624 = 4-1+5-6+2-4
= 4+4-4-4
= 8-8
= 0
0 divisible by 11.
So Answer is 415624.
Form the alternating sum of the digits.
415624 = 4-1+5-6+2-4
= 4+4-4-4
= 8-8
= 0
0 divisible by 11.
So Answer is 415624.
Ish said:
1 decade ago
Can any one explain it more clearly?
Santhu said:
1 decade ago
By sum of all digits can be divisible by 11 also we can calculate.
1. option sum is 21 so it is not divisible with 11
2. option not
3. option not
4. option sum is 22 is divisible by 11
So ans is 4.option
1. option sum is 21 so it is not divisible with 11
2. option not
3. option not
4. option sum is 22 is divisible by 11
So ans is 4.option
Lekha said:
1 decade ago
Ple tell me how the set of numbers are chosen.
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