Aptitude - Numbers - Discussion

Except (4+1+6+5+2+4=22),

Remaining numbers are not divisible by 11.

Odd position - even position.

If it is a case then 2nd option violates it.

Can anyone explain it clearly?

To check whether a number is div by 11, it should satisfy the below condition.

(sum of numbers in odd place) - (sum of numbers in even place) should be = 0 or 11 or divisible of 11.

If sum of all digit will be divisible by 11, the answer will be correct.
Ans=D
4+1+5+6+2+4=22
22 is divisible by11.

Separate the digits into odd and even positions (from right to left).
Sum the digits at odd positions and sum the digits at even positions.

Find the difference between these two sums.
If the difference is 0 or divisible by 11, then the number is divisible by 11.

Thanks @Pooja.

According to the divisible rool (sum odd places-sum of even places).

To check whether a number is divisible by 11, sum the digits in the odd positions counting from the left (the first, third, ....) and then sum the remaining digits. If the difference between the two sums is divisible by 11, then so is the original number. Otherwise it is not.

Why does this work?

I have tried to work it out. My solutions are:

1) if the answer for the subtraction is 0, it is divisible.
2) if the answer for the subtraction is not 0, it is not divisible.

Is the method possible for all numbers? Please tell me.

There is another method as well. In the option A, B, C. If you will add all the digits of the given number the result will not be divisible by 11. But if you will add the digits of the number given in option D.

i.e - 415624=4+1+5+6+2+4=22 which is divisible with 11.

This formula is also applicable for any number.