Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 18)
18.
Which one of the following numbers is exactly divisible by 11?
Answer: Option
Explanation:
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
Discussion:
47 comments Page 3 of 5.
Subbu said:
9 years ago
2+3+5+6+4+1=21 not divisible by 11.
Calculate all given options as the same.
23 not ÷ 11.
21 not ÷ 11.
22 it is divisible by 11 so answer is D.
Calculate all given options as the same.
23 not ÷ 11.
21 not ÷ 11.
22 it is divisible by 11 so answer is D.
Masood tahir said:
1 decade ago
@abhi.
I think Arjun is right as;
209/11= 19 which is completely devise-able by 11 by leaving no remainder, with short cut method for aptitude as; 2+0+9=11 which is also completely divided by 11.
I think Arjun is right as;
209/11= 19 which is completely devise-able by 11 by leaving no remainder, with short cut method for aptitude as; 2+0+9=11 which is also completely divided by 11.
REKHA said:
7 years ago
No, @Abhi.
Because 2+0+9 = 11.
Which is divisible by 11.
Because 2+0+9 = 11.
Which is divisible by 11.
JEBA RAHAT said:
3 months ago
Example:
415624
Position (from right) Digit Position Type
1 4 Odd
2 2 Even
3 6 Odd
4 5 Even
5 1 Odd
6 4 Even
Odd positions: 4, 6, 1
Even positions: 2, 5, 4
sum(odd positions) − sum(even positions)
If that difference is 0 or divisible by 11, the number is divisible by 11.
415624
Position (from right) Digit Position Type
1 4 Odd
2 2 Even
3 6 Odd
4 5 Even
5 1 Odd
6 4 Even
Odd positions: 4, 6, 1
Even positions: 2, 5, 4
sum(odd positions) − sum(even positions)
If that difference is 0 or divisible by 11, the number is divisible by 11.
Anurag nikam said:
1 month ago
Is it necessary that no digits of even and odd should be the same?
Bishnu said:
1 decade ago
I am not understand this method please help me.
Swa said:
2 decades ago
Odd places - Even places = Ans.
Ashutosh said:
2 decades ago
Tell me the method to choose the sets of numbers?
Pradyumna said:
2 decades ago
How the sets of numbers are chosen?
Ali said:
2 decades ago
Is this method applicable for all dividing numbers?
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