Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 18)
18.
Which one of the following numbers is exactly divisible by 11?
Answer: Option
Explanation:
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
Discussion:
47 comments Page 3 of 5.
Amit Chutani said:
1 decade ago
2+3+5+6+4+1 = 21/11.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible.
Arjun said:
1 decade ago
@saurabh.
2+3+5+6+4=20 which is not exactly divisible by 11. It is exactly divisible by 2,5,10,20...
2+3+5+6+4=20 which is not exactly divisible by 11. It is exactly divisible by 2,5,10,20...
Sachin said:
1 decade ago
Sum of digits = (4 + 1 + 5 + 6 + 2 + 4) = 22, which must be divisible by 11.
So answer is 415624.
So answer is 415624.
Vimal said:
1 decade ago
@ pratiksha.
Ya you are right. But in aptitude test, they won't allow you to use calculator!!!
Ya you are right. But in aptitude test, they won't allow you to use calculator!!!
Saranya said:
1 decade ago
odd places - even places will not come because for example 4+6+1 is an odd place
Bhaskar said:
1 decade ago
If you take 209/11.
Then your logic.
Because 2+10+9=21,
21 is not divisible.
Then your logic.
Because 2+10+9=21,
21 is not divisible.
Pratiksha sharma said:
1 decade ago
415624/11=37784.
It is exactly divisible by 11. This is easiest method.
It is exactly divisible by 11. This is easiest method.
Akash said:
7 years ago
According to the divisible rool (sum odd places-sum of even places).
(3)
Pardhu said:
6 years ago
Except (4+1+6+5+2+4=22),
Remaining numbers are not divisible by 11.
Remaining numbers are not divisible by 11.
(24)
Anurag nikam said:
1 month ago
Is it necessary that no digits of even and odd should be the same?
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