Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 18)
18.
Which one of the following numbers is exactly divisible by 11?
235641
245642
315624
415624
Answer: Option
Explanation:

(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.

(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.

(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.

(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.

Discussion:
46 comments Page 2 of 5.

Swar said:   7 years ago
To check whether a number is div by 11, it should satisfy the below condition.

(sum of numbers in odd place) - (sum of numbers in even place) should be = 0 or 11 or divisible of 11.
(8)

Sindhu said:   1 decade ago
2+3+5+6+4+1=21 it is not divisible by 11.

2+4+5+6+4+2=23 it is not divisible by 11.

3+1+5+6+2+4=21 it is not divisible by 11.

4+1+5+6+2+4=22 it is divisible by 11.

Answer:415624.

Vidyadhar said:   1 decade ago
Divisibility rule:

Form the alternating sum of the digits.

415624 = 4-1+5-6+2-4
= 4+4-4-4
= 8-8
= 0

0 divisible by 11.

So Answer is 415624.

Subbu said:   8 years ago
2+3+5+6+4+1=21 not divisible by 11.

Calculate all given options as the same.
23 not ÷ 11.
21 not ÷ 11.

22 it is divisible by 11 so answer is D.

Priyanka P. said:   1 decade ago
@ Ali

No its just for 11..

The difference b/w odd and even numbers total should be 0, 11 or multiple of 11 i.e. 22, 484 etc.

Jessy said:   9 years ago
Take the number and add all the even positions of the number and odd positions of the number then subtract those two.

Pradeep chauhan said:   8 years ago
If sum of all digit will be divisible by 11, the answer will be correct.
Ans=D
4+1+5+6+2+4=22
22 is divisible by11.
(7)

Reena said:   1 decade ago
2+3+5+6+4+1 = 21/11.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible by 11.

Rubeena said:   4 years ago
Odd position - even position.

If it is a case then 2nd option violates it.

Can anyone explain it clearly?
(9)

Ramanchuchra said:   1 decade ago
Can anybody tell me if sum of all digit is divisible by the no. is divisible by the whole set of numbers.


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