Aptitude - Numbers - Discussion

What about x=5 and y=2 as answer?

In explanation, I can't understand last 2 steps.

Please anybody explain them.

Please explain last two step.

we have to make (2x + 4) divisible by 3 bcz we are using (17 + x + y) which is divisible by 3.

Hence to make it divisible by 3 the values are 2 & 8.

In the answer, the given value contain the term 8 for x. So we choose 8 instead of 2.

The values of y corresponding to the value x = 8, is y=5

Please can any one can explain this problem in easy method.

Let the given number be 476 xy 0.

add the digits
(4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.

To check no. is divisible by 3, the easiest way is to check from the options:

from A. put 17+7+4=17+11=28 not divisible by 3
from B. put 17+7+5=17+12=29 not divisible by 3
from C. put 17+8+5=17+13=30 is divisible by 3

therefore,x=8 and y=5.

To check no. is divisible by 11:
(0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
from A. put 7-4-3=7-7=0 is divisible by 11
from B. put 7-5-3=7-8=-1 not divisible by 11
from C. put 8-5-3=8-8=0 is divisible by 11

therefore,x=8 and y=5.

Option C is correct.

Hi Tanya, Thanks for given explanation.

Hey can any one xplain these two steps (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.

And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11. How it comes?

Thank you tanya.

Actually rule for divisbility of 11 is sum of odd places - even places but you did even -odd in the problem. Is it correct?