Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 51)
51.
476 ** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:
7 and 4
7 and 5
8 and 5
None of these
Answer: Option
Explanation:

Let the given number be 476 xy 0.

Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.

And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.

x - y - 3 = 0    y = x - 3

(17 + x + y) = (17 + x + x - 3) = (2x + 14)

x= 2 or x = 8.

x = 8 and y = 5.

Discussion:
37 comments Page 2 of 4.

Roxy said:   1 decade ago
Just try hit and trial method to solve it, by putting the values in the missing places.

Akash said:   1 decade ago
(4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.

How it can be said it must be divisible by 3. Please explain?

Sumit jain said:   1 decade ago
The 1st option is also suiting well in the sum. Then the numbers ll be divisible by both 11 and 3 ?

Priyanka said:   10 years ago
Why not there answer as 7, 4?

Animesh said:   10 years ago
@Akash.

You see that in question it's written that the number, 476**0 is divisible by 3 then the sum of numbers like, (4+7+6+x(x mean *) + y(y mean *)+0) is also be divisible by 3. It's a rule.

Dhanashri said:   9 years ago
Please explain this step, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.

Prateek said:   9 years ago
Thank you so much @Tanya Mazumdar.

Mayank said:   9 years ago
I can't understand please explain me from first step to last step.

Poonam said:   9 years ago
How did y = 5 come?

Harikrishna said:   9 years ago
(0 + x + 7) - (y + 6 + 4) = (x - y -3) .

Please tell me how can we get second line condition please explain in detail, please.


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