Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 22)
22.
753 x 753 + 247 x 247 - 753 x 247 | = ? |
753 x 753 x 753 + 247 x 247 x 247 |
Answer: Option
Explanation:
Given Exp. = | (a2 + b2 - ab) | = | 1 | = | 1 | = | 1 |
(a3 + b3) | (a + b) | (753 + 247) | 1000 |
Discussion:
24 comments Page 3 of 3.
P.s.Deepa said:
1 decade ago
In the denominator
=(753*753*753)+(247*247*247)
=(a*a*a)+(b*b*b)
=a3+b3
Here we assume 753 as "a" and 247 as "b". Since in the denominator 753 is three times so we are writing a^3 and 247 is three times so b^3.
=(753*753*753)+(247*247*247)
=(a*a*a)+(b*b*b)
=a3+b3
Here we assume 753 as "a" and 247 as "b". Since in the denominator 753 is three times so we are writing a^3 and 247 is three times so b^3.
Pavan said:
1 decade ago
How you got in denominator a3+b3?
Pratiksha sharma said:
1 decade ago
a3 + b3= (a + b) (a2 + b2 - ab)
a2+b2-ab/(a+b)(a2+b2-ab)=1/a+b
a2+b2-ab/(a+b)(a2+b2-ab)=1/a+b
Abhishek said:
1 decade ago
Pritika, its simple. Look.
a3 + b3= (a + b) (a2 + b2 - ab). It is maths formula.
Therefore put the formula. You get the answer.
a3 + b3= (a + b) (a2 + b2 - ab). It is maths formula.
Therefore put the formula. You get the answer.
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