Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 22)
22.
| 753 x 753 + 247 x 247 - 753 x 247 | = ? |
| 753 x 753 x 753 + 247 x 247 x 247 |
Answer: Option
Explanation:
| Given Exp. = | (a2 + b2 - ab) | = | 1 | = | 1 | = | 1 |
| (a3 + b3) | (a + b) | (753 + 247) | 1000 |
Discussion:
24 comments Page 3 of 3.
Thula sunya behuria said:
6 years ago
I am not understanding it. Please explain it.
(2)
Jyoti said:
6 years ago
I didn't understand please solve in a simple way.
(4)
Chaitra said:
4 years ago
Formula:(a^3+b^3)=(a+b)(a^2+b^2-ab),
= (a^2+b^2-ab)/(a^3+b^3),
= (a^2+b^2-ab)/(a+b)(a^2+b^2-ab).
= 1/(a+b).
= (a^2+b^2-ab)/(a^3+b^3),
= (a^2+b^2-ab)/(a+b)(a^2+b^2-ab).
= 1/(a+b).
(5)
Imran khan said:
4 years ago
Let a = 753 and b = 247.
Replace all numbers with "a" and "b".
You will get:
a * a + b * b - a * b/a *a * a + b *b * b,
That is, a^2 + b^2 - ab/a^3 + b^3,
As per formula:
(a^2 + b^2 - ab/a^3 + b^3).
(a^3+b^3)=(a+b)(a^2+b^2-ab),
= (a^2+b^2-ab)/(a^3+b^3),
= (a^2+b^2-ab)/(a+b)(a^2+b^2-ab).
= 1/(a+b).
1/(743+247) => 1/1000.
Replace all numbers with "a" and "b".
You will get:
a * a + b * b - a * b/a *a * a + b *b * b,
That is, a^2 + b^2 - ab/a^3 + b^3,
As per formula:
(a^2 + b^2 - ab/a^3 + b^3).
(a^3+b^3)=(a+b)(a^2+b^2-ab),
= (a^2+b^2-ab)/(a^3+b^3),
= (a^2+b^2-ab)/(a+b)(a^2+b^2-ab).
= 1/(a+b).
1/(743+247) => 1/1000.
(10)
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