Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 22)
22.
| 753 x 753 + 247 x 247 - 753 x 247 | = ? |
| 753 x 753 x 753 + 247 x 247 x 247 |
Answer: Option
Explanation:
| Given Exp. = | (a2 + b2 - ab) | = | 1 | = | 1 | = | 1 |
| (a3 + b3) | (a + b) | (753 + 247) | 1000 |
Discussion:
24 comments Page 2 of 3.
Divi said:
9 years ago
Anyone please derive this equation a^3 + b^3 = a^2 + b^2 - ab.
Shweta said:
9 years ago
@Divi.
(a^2 + b^2 - ab)/(a^3 + b^3).
Formula: (a^3 + b^3) = (a+b)(a^2 + b^2 - ab).
(a^2 + b^2 - ab)/(a + b)(a^2 + b^2 - ab) = 1/(a+b).
(a^2 + b^2 - ab)/(a^3 + b^3).
Formula: (a^3 + b^3) = (a+b)(a^2 + b^2 - ab).
(a^2 + b^2 - ab)/(a + b)(a^2 + b^2 - ab) = 1/(a+b).
(1)
Muhammad Ahsan said:
9 years ago
Can anybody explain after this step?
a2+b2-ab / a2+b2-ab.
How 1/a+b comes from that above equation?
a2+b2-ab / a2+b2-ab.
How 1/a+b comes from that above equation?
Farzee said:
8 years ago
(a^3+b^3) = (a+b) (a^2-ab+b^2).
1/(a+b) = (a^2-ab+b^2)/(a^3+b^3).
1/(a+b) = (a^2-ab+b^2)/(a^3+b^3).
(2)
Sriji said:
8 years ago
Explain the formula please.
Arjuna said:
7 years ago
Here, we can use.
(a^3+b^3) = (a+b) (a^2-ab+b^2).
1/(a+b) = (a^2-ab+b^2)/(a^3+b^3).
(a^3+b^3) = (a+b) (a^2-ab+b^2).
1/(a+b) = (a^2-ab+b^2)/(a^3+b^3).
(4)
Arjuna said:
7 years ago
Hi, can anyone explain it in the direct method?
(1)
Zain said:
6 years ago
I am not getting this, Please anyone explain me.
Kiran said:
6 years ago
Can you explain the formula for the answer?
Shipra said:
6 years ago
(753) ^2+(247) ^2-753*247/(753) ^3+(247) ^3.
= (753) +(247) /+(753) ^3+(247) ^3.
= 1/(753) ^2+(247) ^2.
= 1/(753+247).
= 1/1000.
= (753) +(247) /+(753) ^3+(247) ^3.
= 1/(753) ^2+(247) ^2.
= 1/(753+247).
= 1/1000.
(2)
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