Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 33)
33.
How many natural numbers are there between 23 and 100 which are exactly divisible by 6 ?
Answer: Option
Explanation:
Required numbers are 24, 30, 36, 42, ..., 96
This is an A.P. in which a = 24, d = 6 and l = 96
Let the number of terms in it be n.
Then tn = 96 
a + (n - 1)d = 96
24 + (n - 1) x 6 = 96
(n - 1) x 6 = 72
(n - 1) = 12
n = 13
Required number of numbers = 13.
Discussion:
16 comments Page 2 of 2.
Goms said:
1 decade ago
4*6 = 24
5*6 = 30
6*6 = 36
7*6 = 42
8*6 = 48
9*6 = 54
10*6 = 60
11*6 = 66
12*6 = 72
13*6 = 78
14*6 = 84
15*6 = 90
16*6 = 96
TOTAL = 13.
5*6 = 30
6*6 = 36
7*6 = 42
8*6 = 48
9*6 = 54
10*6 = 60
11*6 = 66
12*6 = 72
13*6 = 78
14*6 = 84
15*6 = 90
16*6 = 96
TOTAL = 13.
Avinash said:
1 decade ago
24+(n-1)6 = 96.
= n-1 = 12.
= n = 13.
= n-1 = 12.
= n = 13.
SHIV said:
1 decade ago
Any other method please.
Ramskittu said:
1 decade ago
Max number which or completely divisible by 6 below 100 is 96.
So 96/6 = 16.
Remove before divisible numbers of 23. i.e. 3.
So finally 16-3 = 13.
So 96/6 = 16.
Remove before divisible numbers of 23. i.e. 3.
So finally 16-3 = 13.
Rehana said:
1 decade ago
For example,
Number b/w 15 to 180 divided by 5 are,
180-15+1 = 166.
166/5 = 33.xxx.
Then 33 is the right answer?
Number b/w 15 to 180 divided by 5 are,
180-15+1 = 166.
166/5 = 33.xxx.
Then 33 is the right answer?
Crr said:
2 years ago
Thanks for the explanation.
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