Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 33)
33.
How many natural numbers are there between 23 and 100 which are exactly divisible by 6 ?
8
11
12
13
None of these
Answer: Option
Explanation:

Required numbers are 24, 30, 36, 42, ..., 96

This is an A.P. in which a = 24, d = 6 and l = 96

Let the number of terms in it be n.

Then tn = 96    a + (n - 1)d = 96

24 + (n - 1) x 6 = 96

(n - 1) x 6 = 72

(n - 1) = 12

n = 13

Required number of numbers = 13.

Discussion:
16 comments Page 1 of 2.

Mahesh Patil said:   1 decade ago
Total numbers between 23 to 100 = 100-23+1 = 78

Numbers Divisible by 6 = 78 / 6 =13 (consider Only Quotient ....not Remainder)

Sallick said:   1 decade ago
24+(n-1)6=96
=n-1=12
=n=13

Goms said:   1 decade ago
4*6 = 24
5*6 = 30
6*6 = 36
7*6 = 42
8*6 = 48
9*6 = 54
10*6 = 60
11*6 = 66
12*6 = 72
13*6 = 78
14*6 = 84
15*6 = 90
16*6 = 96
TOTAL = 13.

Avinash said:   1 decade ago
24+(n-1)6 = 96.

= n-1 = 12.

= n = 13.

SHIV said:   1 decade ago
Any other method please.

Anil sarode said:   1 decade ago
@Shiv here is the method for you.

Here total 78 numbers are here, check by AP formula.

Tn = a+(n-1) d where a = 23, d =1, Tn = 100, so n = 78. Now simply divide 78/6 = 13.
(1)

Ramskittu said:   1 decade ago
Max number which or completely divisible by 6 below 100 is 96.

So 96/6 = 16.

Remove before divisible numbers of 23. i.e. 3.

So finally 16-3 = 13.

Nano_Desu said:   10 years ago
How about this one?

100-23 = 77 divided it by 6 77/6 = 12.83 round off 13.
(5)

Rehana said:   9 years ago
For example,

Number b/w 15 to 180 divided by 5 are,

180-15+1 = 166.

166/5 = 33.xxx.

Then 33 is the right answer?

Vijay said:   9 years ago
@Ramskittu.

I am not understanding your method for getting solution. Please explain it again.
(2)


Post your comments here:

Your comments will be displayed after verification.