### Discussion :: Numbers - General Questions (Q.No.33)

Mahesh Patil said: (Aug 1, 2011) | |

Total numbers between 23 to 100 = 100-23+1 = 78 Numbers Divisible by 6 = 78 / 6 =13 (consider Only Quotient ....not Remainder) |

Sallick said: (Apr 21, 2012) | |

24+(n-1)6=96 =n-1=12 =n=13 |

Goms said: (Aug 21, 2013) | |

4*6 = 24 5*6 = 30 6*6 = 36 7*6 = 42 8*6 = 48 9*6 = 54 10*6 = 60 11*6 = 66 12*6 = 72 13*6 = 78 14*6 = 84 15*6 = 90 16*6 = 96 TOTAL = 13. |

Avinash said: (Sep 16, 2013) | |

24+(n-1)6 = 96. = n-1 = 12. = n = 13. |

Shiv said: (Jan 3, 2015) | |

Any other method please. |

Anil Sarode said: (Feb 8, 2015) | |

@Shiv here is the method for you. Here total 78 numbers are here, check by AP formula. Tn = a+(n-1) d where a = 23, d =1, Tn = 100, so n = 78. Now simply divide 78/6 = 13. |

Ramskittu said: (Feb 14, 2015) | |

Max number which or completely divisible by 6 below 100 is 96. So 96/6 = 16. Remove before divisible numbers of 23. i.e. 3. So finally 16-3 = 13. |

Nano_Desu said: (Sep 11, 2015) | |

How about this one? 100-23 = 77 divided it by 6 77/6 = 12.83 round off 13. |

Rehana said: (Mar 10, 2016) | |

For example, Number b/w 15 to 180 divided by 5 are, 180-15+1 = 166. 166/5 = 33.xxx. Then 33 is the right answer? |

Vijay said: (Jun 19, 2016) | |

@Ramskittu. I am not understanding your method for getting solution. Please explain it again. |

Haseeb said: (Aug 1, 2016) | |

The number between 1 to 100 number which a are divisible by 6 is; 6 (100(16 ___ 96 ___ 4. Hence, the number which is divisible between 1 to 100 by 6 are "16". Now we will find the number which is divisible between 1 to 23. 6)23(3 18 _ 5. Hence the number which is divisible between 1 and 23 are "3". Now the number between (1 to 100 ) - ( 1 to 23). 16 - 3 = 13 => Answer. |

Abdul Hasib Laskar said: (Apr 19, 2017) | |

Thanks for explaining this. |

Sarbarth said: (Jul 20, 2017) | |

How can we know which number is perfectly divisible by 78? 9944 or 9988. Can anyone sole it? |

Bhuvana Ram said: (Jun 24, 2019) | |

It was a difficult one to remember the numbers which are divisible by 6. So, I recommended you to solve this by the following method. Formula: n=(l-a)/d+1. For the above question l=100,a=23, d=6. n=((100-23)/6)+1. =(77/6)+1. =77+6/6. = 83/6 = 13 (consider only the quotient, not the remainder). |

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