Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 3 of 4.
Dhannvanth said:
3 years ago
My idea is;
1+4+9=14.
1+5+0=6.
1+5+1=7.
1+6+6=13.
So, according to me, here 6 only can be purely divisible by 6.
1+4+9=14.
1+5+0=6.
1+5+1=7.
1+6+6=13.
So, according to me, here 6 only can be purely divisible by 6.
(6)
Vatsal said:
8 years ago
Number is divided by 6 only when it is perfectly divided by 2 and 3 both.
So Only 150 is divided by both 2 and 3.
So Only 150 is divided by both 2 and 3.
Ayushi said:
1 decade ago
Divisibility rule of 6.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
Mahesh said:
6 years ago
6 = 2 * 3 which are co-actors, then the number divisible by these two will also divisible by 6.
(1)
Vicky kumar verma said:
10 years ago
999/6 = 166 ignore remainder.
99/6 = 16 ignore remainder.
Now, 166-16 = 150 answer.
99/6 = 16 ignore remainder.
Now, 166-16 = 150 answer.
Damini said:
8 years ago
Write numbers from sequence 149 to 387 like 149150159.
How many time does 1 occur?
How many time does 1 occur?
Joshua said:
1 decade ago
What if you try the formula for geometric sequence which is an = a1 x r^n-1.
Sworna said:
1 decade ago
@Mahesh.
Why it is 999-100+1? I can't understand please help me.
Why it is 999-100+1? I can't understand please help me.
Shradha khirid said:
8 years ago
If no is divisible by 3 and 2 then it is easily divisible by 6.
(1)
Harpreet said:
1 decade ago
@Ashish total numbers divisible by 8 comes 112 & not 113.
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