Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 2 of 4.
Amar said:
5 years ago
Lowest 3 digit number which is divisible by 3 is 102.
Highest 3 digit number which is divisible by 3 is 999.
So as per the formula a+(n-1)d=l.
The answer will be 300.
Highest 3 digit number which is divisible by 3 is 999.
So as per the formula a+(n-1)d=l.
The answer will be 300.
Swathi said:
1 decade ago
149:1+4+9 = 16 it is not divisible by 6.
150:1+5+0 = 6 it is divisible by 6.
151:1+5+1 = 7 not divisible by 6.
166:1+6+6 = 13 not divisible by 6.
Ans :150 (B).
150:1+5+0 = 6 it is divisible by 6.
151:1+5+1 = 7 not divisible by 6.
166:1+6+6 = 13 not divisible by 6.
Ans :150 (B).
Ishan said:
1 decade ago
Directly, on dividing 150 by 6 gives o as a reminder and as a quotient it gives 25 so that 150 comes in the multiple of 25 in the 6 place.
150/6 = 25.
25*6 = 150.
150/6 = 25.
25*6 = 150.
Samir said:
1 decade ago
It can take any no.of digit so,
Last digit - first digit(996-102) = 894.
Divide by divisible no. 894/6 = 149.
In formula opposite (n-1) +1.
(149+1) = 150.
Last digit - first digit(996-102) = 894.
Divide by divisible no. 894/6 = 149.
In formula opposite (n-1) +1.
(149+1) = 150.
Anand said:
4 years ago
Let the highest 3 digit num divided by 6 is 996,
then 996/6= 166.
Let the highest 2 digit num divided by 6 is 96,
then 96/6= 16,
Now 166-16= 150.
then 996/6= 166.
Let the highest 2 digit num divided by 6 is 96,
then 96/6= 16,
Now 166-16= 150.
(21)
Vivek said:
1 decade ago
Adding the given three deghit it means =150
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
Mahesh Patil said:
1 decade ago
Total Three digit numbers = 999-100+1 = 900
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
Tanoy Saha said:
2 years ago
149 is not divisible by 6.
150 is divisible by 6.
151 is not divisible by 6.
166 is not divisible by 6.
So, the right answer is 150.
150 is divisible by 6.
151 is not divisible by 6.
166 is not divisible by 6.
So, the right answer is 150.
(8)
Rohit said:
9 years ago
100 - 999 these are three digits no,
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
Rahul said:
9 years ago
Please give me a solution for "What is the sum of 3 digits number which is completely divisible by 3, then find the sum".
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