Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 2 of 4.
Udaya santhi said:
1 decade ago
6 written as 2*3.
The number completely divisible by both numbers 2&3.
If the number is divisible by 2 that number should be an even.
If the number is divisible by 3 then taken sum of digits.
Option verification:
Only two even numbers are there 150 & 166.
These two numbers are divisible by 2.
1+5+0 = 6(which is divisible by 3), 1+6+6 = 13(which is not divisible by 3).
Hence 150 is the answer.
The number completely divisible by both numbers 2&3.
If the number is divisible by 2 that number should be an even.
If the number is divisible by 3 then taken sum of digits.
Option verification:
Only two even numbers are there 150 & 166.
These two numbers are divisible by 2.
1+5+0 = 6(which is divisible by 3), 1+6+6 = 13(which is not divisible by 3).
Hence 150 is the answer.
Swathi said:
1 decade ago
149:1+4+9 = 16 it is not divisible by 6.
150:1+5+0 = 6 it is divisible by 6.
151:1+5+1 = 7 not divisible by 6.
166:1+6+6 = 13 not divisible by 6.
Ans :150 (B).
150:1+5+0 = 6 it is divisible by 6.
151:1+5+1 = 7 not divisible by 6.
166:1+6+6 = 13 not divisible by 6.
Ans :150 (B).
Ishan said:
1 decade ago
Directly, on dividing 150 by 6 gives o as a reminder and as a quotient it gives 25 so that 150 comes in the multiple of 25 in the 6 place.
150/6 = 25.
25*6 = 150.
150/6 = 25.
25*6 = 150.
Samir said:
1 decade ago
It can take any no.of digit so,
Last digit - first digit(996-102) = 894.
Divide by divisible no. 894/6 = 149.
In formula opposite (n-1) +1.
(149+1) = 150.
Last digit - first digit(996-102) = 894.
Divide by divisible no. 894/6 = 149.
In formula opposite (n-1) +1.
(149+1) = 150.
Ayushi said:
1 decade ago
Divisibility rule of 6.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
Joshua said:
1 decade ago
What if you try the formula for geometric sequence which is an = a1 x r^n-1.
Vicky kumar verma said:
10 years ago
999/6 = 166 ignore remainder.
99/6 = 16 ignore remainder.
Now, 166-16 = 150 answer.
99/6 = 16 ignore remainder.
Now, 166-16 = 150 answer.
Rahul said:
9 years ago
Please give me a solution for "What is the sum of 3 digits number which is completely divisible by 3, then find the sum".
Samir Das said:
9 years ago
Thanks for the answer. It's useful to me.
Rohit said:
9 years ago
100 - 999 these are three digits no,
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
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