Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 4 of 4.
Anand said:
4 years ago
Let the highest 3 digit num divided by 6 is 996,
then 996/6= 166.
Let the highest 2 digit num divided by 6 is 96,
then 96/6= 16,
Now 166-16= 150.
then 996/6= 166.
Let the highest 2 digit num divided by 6 is 96,
then 96/6= 16,
Now 166-16= 150.
(21)
Dhannvanth said:
3 years ago
My idea is;
1+4+9=14.
1+5+0=6.
1+5+1=7.
1+6+6=13.
So, according to me, here 6 only can be purely divisible by 6.
1+4+9=14.
1+5+0=6.
1+5+1=7.
1+6+6=13.
So, according to me, here 6 only can be purely divisible by 6.
(6)
Tanoy Saha said:
2 years ago
149 is not divisible by 6.
150 is divisible by 6.
151 is not divisible by 6.
166 is not divisible by 6.
So, the right answer is 150.
150 is divisible by 6.
151 is not divisible by 6.
166 is not divisible by 6.
So, the right answer is 150.
(8)
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