Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 76)
76.
A number when divide by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is:
Answer: Option
Explanation:
Let x = 6q + 3.
Then, x2 = (6q + 3)2
= 36q2 + 36q + 9
= 6(6q2 + 6q + 1) + 3
Thus, when x2 is divided by 6, then remainder = 3.
Discussion:
11 comments Page 2 of 2.
Ameena asma said:
7 years ago
As we know Dividend = Divisor * Quotient + Remainder.
D = (6*Q) + 3 -------> (1)
Its square root means D^2 = R -------> (2)
Substitute eqtn 1 into 2.
[(6*Q)+3]^2/6 = R
Take Q = 1.
Then, (6+3)^2/6 = R.
Therefore R = 3.
D = (6*Q) + 3 -------> (1)
Its square root means D^2 = R -------> (2)
Substitute eqtn 1 into 2.
[(6*Q)+3]^2/6 = R
Take Q = 1.
Then, (6+3)^2/6 = R.
Therefore R = 3.
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