# Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 34)

34.

How many of the following numbers are divisible by 3 but not by 9 ?

2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276

2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276

Answer: Option

Explanation:

Marking (/) those which are are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get:s

2133 9 (X)

2343 12 (/)

3474 18 (X)

4131 9 (X)

5286 21 (/)

5340 12 (/)

6336 18 (X)

7347 21 (/)

8115 15 (/)

9276 24 (/)

Required number of numbers = 6.

Discussion:

12 comments Page 1 of 2.
Mr.Prakash said:
2 years ago

Thank you very much @Ram,

Very helpful solution.

Very helpful solution.

Roobi said:
2 years ago

@Ajax.

It's quite easy to understand. Thanks.

It's quite easy to understand. Thanks.

Chintu said:
3 years ago

Thank you soo much @Ajax.

It is very simply to understand.

It is very simply to understand.

Ujjwal said:
4 years ago

A number divisible by 9 must be divisible by 3.

Anomis said:
5 years ago

5340 is not divisible by 9.

So, the answer is (A).

So, the answer is (A).

Ram said:
6 years ago

A number divisible by 9- sum of all those digits should be divisible by 9.

Reshmaa said:
7 years ago

In shortcut, how to check whether a number is divisible by 9 and not by 3?

Aishu said:
8 years ago

Shortcut method:

To check a number divisible by 9- sum of all those digits should be divisible by 9.

Just add all those digits in each no and check if /9.

To check a number divisible by 9- sum of all those digits should be divisible by 9.

Just add all those digits in each no and check if /9.

Ajax said:
8 years ago

Simple sum of the number, if sum is only divide by 3 so that answer like.

(2+1+3+3) = 9 is divide by both 3 and 9.

(2+3+4+3) = 12 is only divide by 3.

Check all.

(2+1+3+3) = 9 is divide by both 3 and 9.

(2+3+4+3) = 12 is only divide by 3.

Check all.

Manish said:
9 years ago

Sir please give us a short-cut method for doing this question.

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