Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 37)
37.
A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
Answer: Option
Explanation:
4 a 3 | 9 8 4 } ==> a + 8 = b ==> b - a = 8 13 b 7 |
Also, 13 b7 is divisible by 11 
(7 + 3) - (b + 1) = (9 - b)
(9 - b) = 0
b = 9
(b = 9 and a = 1) (a + b) = 10.
Discussion:
35 comments Page 4 of 4.
Prudvj said:
8 years ago
4 digit number 13b7 i. e divided 11.
So even-odd then :(3+7)-(1+b )apply b=9.
10-10=0.
a+b=1+9=10.
So even-odd then :(3+7)-(1+b )apply b=9.
10-10=0.
a+b=1+9=10.
(3)
Soni said:
8 years ago
Guys, 11 divisibility rule is applicable here so solve it by that rule. It will be more easy.
(3)
Chitra said:
7 years ago
Nice explain @Samyuktha.
(3)
Nandini B N said:
5 years ago
To know the number is divisible by 11, the rule is,
Sum of all even places=sum of all odd places.
In 13b7,
3 + 7 = 1 + b.
b=9.
Then a+8 = 9.
a = 1.
a+b = 1 + 9 = 10.
Sum of all even places=sum of all odd places.
In 13b7,
3 + 7 = 1 + b.
b=9.
Then a+8 = 9.
a = 1.
a+b = 1 + 9 = 10.
(52)
Deepika said:
3 years ago
@Uma.
Super, Thanks for explaining.
Super, Thanks for explaining.
(5)
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