Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 37)

Numbers

37.

A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?

Answer: Option

Explanation:

 4 a 3  |
 9 8 4  }  ==> a + 8 = b  ==>  b - a = 8  
13 b 7  |

Also, 13 b7 is divisible by 11 (7 + 3) - (b + 1) = (9 - b)

(9 - b) = 0

b = 9

(b = 9 and a = 1) (a + b) = 10.

Discussion:

35 comments Page 3 of 4.

Soma said: 1 decade ago

I could not get why 13b7 divisible 11 was represented as (7+3) - (b+1). ?

M.devi said: 1 decade ago

I couldn't understand this problem please say it in another method.

(1)

Sai said: 1 decade ago

Guys i'm confused, how com we take a+8, is there simple method?

Manojit Kar said: 1 decade ago

->211* 11=2321
now (2+2)-(3+1)=0.
simplify u got (9 - b)=0

Md. Mahbubur Rahaman Sheikh said: 2 decades ago

How can you got (9 - b) I cannot understand. Please, Explain

Senthil kumar said: 1 decade ago

Here a=1 is how declared please explain I can't understand?

(1)

Saini ji said: 8 years ago

But what about condition that 13b7 is divisible by 11.

(1)

BhargaV said: 1 decade ago

-> (7 + 3) - (b + 1)

simplify this u got (9 - b)

Nadeeshani said: 1 decade ago

How do we get (9 - b) = 0 Please explain.....

Deepika said: 3 years ago

@Uma.

Super, Thanks for explaining.

(5)

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers