Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option
Explanation:
| log5 512 |
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| = 3.876 |
Discussion:
71 comments Page 5 of 8.
Nirav said:
1 decade ago
Why are they dividing log 512 by log 5?
Is this a formula?
Is this a formula?
Apoorva said:
1 decade ago
Why is it only 2?
K.rajeshreddy said:
1 decade ago
log5512 = log512/log5 = 9log2/log5.
= 9log2/log3+log2.
= 9*0.3010/0.4771+0.3010.
I think this is this the correct procedure as log 2 and log3 values are given. Why we need to go for log 10/2?
= 9log2/log3+log2.
= 9*0.3010/0.4771+0.3010.
I think this is this the correct procedure as log 2 and log3 values are given. Why we need to go for log 10/2?
Lekan said:
1 decade ago
Please who can solve this log10 2 = 0.3010?
Vigneshraj said:
1 decade ago
@jeromy.
Click the impotant formulas link there you can see 7th formula using that formula we divide log512 by log5.
Click the impotant formulas link there you can see 7th formula using that formula we divide log512 by log5.
Vipin Mishra said:
1 decade ago
Formula:
log a x = log x/log a.
log 5 512 = log 512/log 5.
log a x = log x/log a.
log 5 512 = log 512/log 5.
Usha said:
1 decade ago
If log2=0.3010 and log3= 0.4771, then log75 = ?
Sinkay said:
1 decade ago
If log 2=0.3010 and log 7=0.8451,
Shalini said:
1 decade ago
@Kasthuri
log 75= log(5*5*3) = log(5*5)+log(3), because log m*n=log m+log n
=2 log5 +log3
=2 log(10/2)+log3
=2(log10-log2)+log3
=2(1-.3010)+..4771
=2*.699+.4771
=1.398+.4771
=1.8751
log 75= log(5*5*3) = log(5*5)+log(3), because log m*n=log m+log n
=2 log5 +log3
=2 log(10/2)+log3
=2(log10-log2)+log3
=2(1-.3010)+..4771
=2*.699+.4771
=1.398+.4771
=1.8751
Heaven.bangladesh said:
1 decade ago
@sumit
Log 5=log(10/2).coz,10/2=5
Log 5=log(10/2).coz,10/2=5
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